Difference between revisions of "Probability RV Exercises"

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= Probability Exercises =
 
= Probability Exercises =
  
Solutions in {curly brackets}. Worked solution clips can be found here [http://youtu.be/GsHP3gMwqI8?hd=1 Q1], [ Q2], [ Q3], and [ Q5].
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Levels in [square brackets] and solutions in {curly brackets}. Worked solution clips can be found here [http://youtu.be/GsHP3gMwqI8?hd=1 Q1], [http://youtu.be/4zSRlomN6q4?hd=1 Q2], [http://youtu.be/GnJ0_DEymxI?hd=1 Q3], [http://youtu.be/lFkoxN4QO0M?hd=1 Q4] and [http://youtu.be/4MwFJog0kSo?hd=1 Q5].
  
 
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\right.</math></p></li>
 
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<li><p>Show the probability that a component will operate for at least <math>200</math> hours without failure is <math>\Pr (T\geq 2)\cong 0.135</math>.?</p></li>
 
<li><p>Show the probability that a component will operate for at least <math>200</math> hours without failure is <math>\Pr (T\geq 2)\cong 0.135</math>.?</p></li>
<li><p>Three of these electrical components operate independently of one another in a piece of equipment and the equipment fails if ANY ONE of the individual components fail. What is the probability that the equipment will operate for at least <math>200</math> hours without failure? (Use the result in (5.2) in a binomial context).</p></li></ol>
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<li><p>Three of these electrical components operate independently of one another in a piece of equipment and the equipment fails if ANY ONE of the individual components fail. What is the probability that the equipment will operate for at least <math>200</math> hours without failure? (Use the result in (5.2) in a binomial context). {0.0025}</p></li></ol>
 
</li></ol>
 
</li></ol>
  
 
= Footnotes =
 
= Footnotes =

Latest revision as of 07:48, 28 August 2014


Probability Exercises

Levels in [square brackets] and solutions in {curly brackets}. Worked solution clips can be found here Q1, Q2, Q3, Q4 and Q5.

  1. [math][L1,L2][/math] In an experiment, if a mouse is administered dosage level [math]A[/math] of a certain (harmless) hormone then there is a [math]0.2[/math] probability that the mouse will show signs of aggression within one minute. For dosage levels [math]B[/math] and [math]C[/math], the probabilities are [math]0.5[/math] and [math]0.8[/math], respectively. Ten mice are given exactly the same dosage level of the hormone and, of these, exactly [math]6[/math] shows signs of aggression within one minute of receiving the dose.

    1. Calculate the probability of this happening for each of the three dosage levels, [math]A,B[/math] and [math]C[/math]. (This is essentially a Binomial random variable problem, so you can check your answers using EXCEL.) {0.0055; 0.2051; 0.0881}

    2. Assuming that each of the three dosage levels was equally likely to have been administered in the first place (with a probability of [math]1/3[/math]), use Bayes’ Theorem to evaluate the likelihood of each of the dosage levels given that [math]6[/math] out of the [math]10[/math] mice were observed to react in this way. Most likely that dosis B was administered.

  2. [math][L1,L2][/math] Let [math]X[/math] be the random variable indicating the number of incoming planes every [math]k[/math] minutes at a large international airport, with probability mass function given by [math]p(x)=\Pr (X=x)=\frac{(0.9k)^{x}}{x!}\exp (-0.9k),\quad x=0,1,2,3,4,..[/math]. Find the probabilities that there will be

    1. exactly [math]9[/math] incoming planes during a period of [math]5[/math] minutes (i.e., find [math]\Pr (X=9)[/math] when [math]k=5)[/math]; { 0.02316}

    2. fewer than [math]5[/math] incoming planes during a period of [math]4[/math] minutes (i.e., find [math]\Pr (X\lt 5)[/math] when [math]k=4)[/math]; { 0.7065}

    3. at least [math]4[/math] incoming planes during an [math]2[/math] minute period (i.e., find [math]\Pr (X\geq 4)[/math] when [math]k=2)[/math]. { 0.1087}

    Check all your answers using EXCEL.

  3. [math][L2][/math] The random variable [math]Y[/math] is said to be Geometric if it has probability mass function given by [math]p(y)=\Pr (Y=y)=(1-\theta )\theta ^{y-1},\quad y=1,2,3,...;\quad 0\lt \theta \lt 1[/math]; where [math]\theta [/math] is an unknown ‘parameter’.

    Show that the cumulative distribution function can be expressed as

    [math]P(y)=\Pr (Y\leq y)=1-\theta ^{y},\quad y=1,2,3,...[/math]

    with [math]P(y)=0[/math] for [math]y\leq 0[/math] and [math]P(y)\rightarrow 1[/math] as [math]y\rightarrow \infty. [/math]

    (Note that [math]P(y)=p(1)+p(2)+...+p(y)=\sum_{t=1}^{y}p(t)[/math] can be written in longhand as

    [math]P(y)=\left( 1-\theta \right) \left( 1+\theta +\theta ^{2}+\theta ^{3}+\ldots +\theta ^{y-1}\right) .[/math]

    The term in the second bracket on the right-hand side is the sum of a Geometric Progression.)

  4. [math][L2][/math] The weekly consumption of fuel for a certain machine is modelled by means of a continuous random variable, [math]X[/math], with probability density function

    [math]g(x)=\left\{ \begin{array}{c} 3(1-x)^{2},\quad 0\leq x\leq 1, \\ 0,\quad \text{otherwise}.\end{array} \right.[/math]

    Consumption, [math]X[/math], is measured in hundreds of gallons per week.

    1. Verify that [math]\int_{0}^{1}g(x)dx=1[/math] and calculate [math]\Pr (X\leq 0.5)[/math].

    2. How much fuel should be supplied each week if the machine is to run out fuel [math]10\%[/math] of the time at most? (Note that if [math]s[/math] denotes the supply of fuel, then the machine will run out if [math]X\gt s[/math].) Find the formula you need to solve and find an approximate solution. {approximately 0.54}

  5. [math][L2][/math] The lifetime of a electrical component is measured in [math]100[/math]s of hours by a random variable [math]T[/math] having the following probability density function

    [math]f(t)=\left\{ \begin{array}{c} \exp (-t),\quad t\gt 0, \\ 0,\quad \text{otherwise}.\end{array} \right.[/math]

    1. Show that the cumulative distribution function, [math]F(t)=\Pr (T\leq t)[/math] is given by

      [math]F(t)=\left\{ \begin{array}{ll} 1-\exp (-t), & t\gt 0 \\ 0 & t\leq 0.\end{array} \right.[/math]

    2. Show the probability that a component will operate for at least [math]200[/math] hours without failure is [math]\Pr (T\geq 2)\cong 0.135[/math].?

    3. Three of these electrical components operate independently of one another in a piece of equipment and the equipment fails if ANY ONE of the individual components fail. What is the probability that the equipment will operate for at least [math]200[/math] hours without failure? (Use the result in (5.2) in a binomial context). {0.0025}

Footnotes