Difference between revisions of "ArrayStructures"
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Revision as of 00:46, 11 October 2012
=1.0
Contents
Intro
Sometimes you would like to store data which have more than two dimensions. For example, interest rates for different maturities for different countries over time. In this case there are three natural indices: country index, maturity index, and time. Another example could be regression results of Monte-Carlo simulations for different sample sizes and different model specifications. In MATLAB you can address this issue using three different approaches:
- Multidimensional arrays
- Structures/Structure Arrays
- Cells/Cell arrays
In the next sections we will briefly review these data objects and discuss the most straightforward way to handle them.
Multidimensional Arrays
Elementwise Operations
Multidimensional arrays are just a generalization of a matrix. Almost all MATLAB functions can generate and operate with multivariate arrays, for example, to generate a three-dimensional array of normal random numbers with dimensions [math]T,p,k[/math], you have to type:
A=randn(T,p,k);
MATLAB prints all multidimensional arrays as a sequence of matrices. Say, [math]2\times 2\times 2[/math] array is printed as
>> A=zeros(2,2,2)
A(:,:,1) =
0 0
0 0
A(:,:,2) =
0 0
0 0
Taking an average over the second dimension and taking a maximum over the third dimension looks like:
meanA=mean(A,2);
maxA=max(A,[],3);
Please note the syntax of max
function. For this function the second argument stands for a matrix/scalar that you are comparing with your matrix A. If you don’t want to experience any surprises, please check with the function help first. Multidimensional arrays support element-by-element operations (operations with dots), as well as operations with scalars. MATLAB will correctly compute
B=A.^2;
C=A.^B+B;
D=C./A;
In the first line, 3-D array B consists of squared values of 3-D array A. In the second line elements of 3-D array C consist of elements of A in power of elements B plus elements from B. 3-D array D consists of element-wise division of C by A. However, the following commands
A*A;
A^2;
will throw an error, since ^,*
are matrix operations and they are not defined on multidimensional arrays.
Collapsing Singleton Dimensions
All operations of extracting sub-arrays from these arrays work as usual (see link). However, there are some particularities that I would like to mention. Assume that we have a [math]3\times 3\times 3[/math] array A. MATLAB recognizes the following operation :
A(:,:,1)*A(:,:,2);
while
A(1,:,:)*A(1,:,:);
generates an error. We get the same result if we try to plot our data:
plot(A(:,:,1))
plots a figure, while
plot(A(1,:,:))
generates an error. It happens because from MATLAB point of view A(1,:,:)
is not a matrix, it is still a 3-D array. There are two ways to deal with this issue:
Make MATLAB realize that we would like to see a matrix instead of a 3-D array with a singleton in the first dimension
B(:,:)=A(1,:,:); plot(B)
Collapse all singleton dimensions using a special command
squeeze
B=squeeze(A(1,:,:)); plot(B)
Expanding to Higher Dimensions
By default, element-wise operations and operations with a scalar are defined on any multi-dimensional array. An additional set of operations is defined on conformable vectors and matrices. The natural question to ask is “What to do if you want to subtract a vector from a matrix, or a matrix from N-D array?” In MATLAB there is a special command that can create a higher-dimensional array from a lower-dimensional one via replication:
A=repmat([1,2,3]',2,3)
A =
1 1 1
2 2 2
3 3 3
1 1 1
2 2 2
3 3 3
replicates a column-vector [math][1\ 2\ 3]'[/math] twice along each row and 3 times along each column. For 3-D vector replication we have to use slightly different syntax:
A=repmat([1,2,3]',[1 2 3])
A(:,:,1) =
1 1
2 2
3 3
A(:,:,2) =
1 1
2 2
3 3
A(:,:,3) =
1 1
2 2
3 3
This command does not change the length of the vector, but replicates it twice along the second dimension and 3 times along the third dimension. Consider the following two real-life examples:
- Assume that we have a cross-section of returns and we would like to subtract a series of risk-free rate
- Assume that we need to subtract a mean along the third dimension from a 3-D array.
For the first example we can use loop:
% rf - a series of risk-free returns
% R - a cross-section of returns, it is assumed that size(R,1)=size(rf,1)
R=zeros(size(R));
for i=1:size(R,2)
Rex(:,i)=R(:,i)-rf;
end
or repmat
command:
% rf - a series of risk-free returns
% R - a cross-section of returns, it is assumed that size(R,1)=size(rf,1)
Rf=repmat(rf,1,size(R,2));
Rex=R-Rf;
For the second example, to implement loop, we have to:
- Compute a mean of 3-D array
- Initiate a 3-D array of demeaned values
- Subtract piece-by-piece a matrix of means from each layer of the 3-D array
- check whether the mean is indeed subtracted
R=rand(3,4,10); % constructing a 3-D array of U(0,1) random variables
Rmean3=mean(R,3); %constructing a matrix of means
Rdemean=zeros(size(R)); %initializing a 3-D array of zeros
for i=1:size(R,3)
Rdemean(:,:,i)=R(:,:,i)-Rmean3;
end
disp(mean(Rdemean,3)) % which is a matrix of zeros implying we worked correctly
- Compute a mean of 3-D array
- Construct a 3-D array of means
- subtract one from another
- check whether the mean is indeed subtracted
R=rand(3,4,10); % constructing a 3-D array of U(0,1) random variables
Rmean3=mean(R,3); %constructing a matrix of means
Rmean3expand=repmat(Rmean3,[1 1 size(R,3)]); %Please note, for more than 2-dimensional arrays, repmat accepts a vector of replications instead of a variable number of inputs.
Rdemean=R-Rmean3expand;
disp(mean(Rdemean,3)) %matrix of zeros, which mean that we did it correctly
Obviously, there are many ways of handling these problems.
Each of these approaches has its advantages and disadvantages. For example: the easiest way to handle data in a uniform way is to use multidimensional arrays. Multivariate arrays, however, require that the data are of the same type (logical, numerical, character).
Structures and Cell Arrays
Sometimes it is natural to keep data of different type under the same roof, i.e. using the same variable name. Multidimensional arrays do not allow that. Therefore structures/arrays of structures or cell arrays have to be used. These two objects are very similar and, in fact, interchangeable. For some applications, however, cell arrays are more suitable while, for other, structures are preferable. For obvious reasons, arithmetic operations are not defined.
Structures
A structure variable is a variable that has “fields”. The variable name is separated from field name by a dot. For example, if you want to keep all OLS regression results, i.e. beta coefficients, covariance matrix, t-stats and vector of residuals in one place.
%Assuming X and y are already defined, the whole filling-up process of the structure would look as follows:
OLS.beta=X\y;%short and more efficient way to write inv(X'*X)*X'*y
OLS.resid=y-X*OLS.beta;
[T,k]=size(X);
OLS.sigma2=sum(OLS.resid.^2)/(T-k);%computing residual variance
OLS.cov=OLS.sigma2*inv(X'*X);
OLS.tstat=OLS.beta./sqrt(diag(OLS.cov));
OLS.name='Regression one';
Any assignment of this variable to another one creates a copy of the structure with all fields and values defined.
>> OLSnew=OLS;
>> OLSnew.name
ans =
Regression one
A field can be a structure by itself. For example,
>> OLSnew.old=OLS;
>> OLSnew.old.name
ans =
Regression one
Moreover, all fields will be carried in and out of a function. In this way you should not care about the order of inputs and outputs for a function with many inputs/outputs. There are several useful functions that you can use with structures:
>> isfield(OLS,'name')
ans =
1
>> isfield(OLS,'pvalues')
ans =
0
This command checks the existence of a particular field within the structure. You can also get a list of all fields within a current structure using fieldnames
>> fnames=fieldnames(OLSnew)'
fnames =
'beta' 'resid' 'sigma2' 'cov' 'tstat' 'name' 'old'
This command creates a cell array (see Section [cell]) fnames
with field names of OLSnew structure. You can also access the values of these field names using indirect referencing. In particular,
>> OLSnew.(fnames{6}) %please note curly brackets!
ans =
Regression one
Since fnames{6}=’name’
and, as a result, we indirectly refer to the field name
of the structure OLSnew
. In this way we can compare two structures field-by-field. Other useful commands for working with structure field names are:
-
intersect(A,B)
, in terms of set operations, it corresponds to [math]A\cap B[/math] -
union(A,B)
, corresponds to [math]A\cup B[/math] -
setdiff(A,B)
, corresponds to [math]A/B[/math] (please note, [math]A/B \ne B/A[/math]) -
setxor(A,B)
, corresponds to [math](A/B)\cup (B/A)[/math]
f1={'first','second'}; %Creating a cell array, see next section for details
f2={'second','third'}; %Creating a cell array, see next section for details
>> disp(intersect(f1,f2))
'second'
>> disp(union(f1,f2))
'first' 'second' 'third'
>> disp(setdiff(f1,f2))
'first'
>> disp(setdiff(f2,f1))
'third'
>> disp(setxor(f1,f2))
'first' 'third'
You can collect structures in arrays. Please note, all member structures of an array have to have the same set of fields. Creating a field for one element of the array, you are automatically creating empty fields of the same name for all members of your array. However, despite the fact that the field names are the same, there are no restriction on the field types. Example:
>> s(2).f1=1;
>> disp(s(1))
f1:[];
>> s(2).f2='Sally';
>> disp(s(1))
f1:[]
f2:[]
>> s(1).f1=3;
>> s(1).f2=[83 116 117 100 101 110 116 32];
You can print all values of a structure field in an array using “:” operator:
>> s(:).f1
ans =
3
ans =
1
>> s(:).f1
ans =
83 116 117 100 101 110 116 32
ans =
Sally
and try to construct an array out of them using concatenation operator [ ]:
[s(:).f1]
ans =
3 1
though results may vary (try to figure it out by yourself):
[s(:).f2]
ans =
Student Sally
An additional hint:
[s(:).f2]+0
ans =
83 116 117 100 101 110 116 32 83 97 108 108 121
Some MATLAB functions require structures as inputs (See non-linear optimization for details). Other MATLAB functions return structures when they are asked. For example, data=load(fname)
creates a structure data
with fieldnames that coincide with variables of the workspace saved in the data file fname
. Thus, for comparing variables from different MATLAB data files, we first need to create two structures:
data1=load(fname1);
data2=load(fname2);
You can automatically compare variables with the same names from these datasets, using intersect
and setdiff
commands:
data1=load('data1');%data1.mat has to exist
data2=load('data2');%data2.mat has to exist
if isequal(data1,data2)
disp('These structures are the same')
else
fname1=fieldnames(data1);
fname2=fieldnames(data2);
fnamejoint=intersect(fname1,fname2);
for i=1:length(fnamejoint)
if isequal(data1.(fnamejoint{i}),data2.(fnamejoint{i}))
disp([fnamejoint{i} ' fields are the same'])
else
disp([fnamejoint{i} ' fields are different'])
end
end
disp('Unique for data1:')
disp(setdiff(fname1,fname2)')
disp('Unique for data2:')
disp(setdiff(fname2,fname1)')
end
Please note: the script above detects only limited number of “equality” cases. Due to a finite number of digits reserved for storing a number in memory (32 bits for double, 16 bit for single), the final result may depend on the computing path. For example, in theory, [math]\ln(\exp(x))\equiv x[/math]. In reality this is not exactly the case. If we generate a [math]1000\times 1[/math] vector of random numbers a
and compare it with log(exp(a))
, we obtain slightly different results. Thus, a standard comparison using isequal
does not work:
>> a=rand(1000,1);
>> isequal(a,log(exp(a)))
ans =
0
>> disp(mean(a-log(exp(a))))
9.9335e-17
As a result, if you want to compare two numbers/vectors/arrays, you have to specify your tolerance level and compare not vectors or matrices, but rather a measure of a distance between the two:
%function that compares two vectors with predefined tolerance level tol:
function out=myisequal(a,b,tol)
if mean(abs(a-b))>tol %checks whether an average absolute difference between two vectors is larger than the tolerance level.
out=0; %if "Yes", then these two vectors are different given the current tolerance level
else
out=1; %if "No", then these two vectors are equal given the current tolerance level
end
Another command that generates a (possibly empty) array of structures is dir(file_mask)
. To obtain a list of all mat files in the current directory, you have to type:
>> matfiles=dir('*.mat')
matfiles =
1004x1 struct array with fields:
name
date
bytes
isdir
datenum
Then you can load all these files to memory (if you have enough of RAM). If all mat files in the directory have the same variables, you can load all of them by constructing a standard vector of structures. However, if the number of variables varies from file to file, using cell arrays would be a better idea (for details, see next section).
Cell Arrays[cell]
The least structured variable type in MATLAB is cell array. You can store a sequence of any data objects in it. You may want to think about cell arrays as a structure where each field is coded by one number (if it is one-dimensional) or some set of numbers, if it is multidimensional. Since everything is coded by numbers, it is easier to use cell arrays inside loops. However, since sequence of numbers is not as informative as structure field names, it is harder to follow. Cell arrays are defined using curly brackets:
>> c={'test',rand(10),1:10 }
c =
'test' [10x10 double] [1x10 double]
The same result can be achieved in three steps:
>> c{1}='test';
>> c{2}=rand(10);
>> c{3}=1:10;
>> c
c =
'test' [10x10 double] [1x10 double]
To refer to the second element of c(3)
, the following syntax has to be employed:
>> c{3}(2)
ans =
2
Important:
There is a very important difference between c(3)
and c{3}
. The former refers to [math]1\times 1[/math] cell array, while the second refers to its value.
>> mean(c(3));
Undefined function 'sum' for input arguments
of type 'cell'.
Error in mean (line 28)
y = sum(x)/size(x,dim);
Since math functions are not defined on cell variables, while
>> mean(c{3})
ans =
5.5000
works as expected. By the same logic, the assignment below
c(4:5)={'ostrich', randn(50)};
works by extending cell array c
to [math]5\times 1[/math], while
c{4:5}={'ostrich', randn(50)};
generates an error. Also an error is generated by
c(6)=randn(4);
as we are trying to assign a double array randn(4)
to a cell element c(6)
. The correct assignment is
c(6)={randn(4)};
Curly brackets convert double array to a cell element, and you can assign a cell element to another cell element.
Now, equipped with this information, we can load all mat files in current directory in MATLAB using cell arrays:
fname=dir('*.mat');
for i=1:length(fname)
data{i}=load(fname(1).name);
end
The same goal can be achieved using structure:
fname=dir('*.mat');
for i=1:length(fname)
curr_field=['f' fname(i).name(1:end-4)];%Filename is selected, .mat is dropped. The leading 'f' stands for a file. Please note that the code might not work for some file names
data.(curr_field)=load(fname(1).name);
end
It is possible to convert structures to cell arrays and vice versa. Also, it is possible to apply a function to each cell of a cell array
c = struct2cell(s)
converts a structures
to a cell arrayc
, fields are converted to cells using the same order as in structures
s = cell2struct(c,fields)
converts a cell arrayc
to a structure arrays
with fieldnames defined infields
>> s=struct('f1',rand(10),'f2','MSFT') %an alternative way to create a structure s = f1: [10x10 double] f2: 'MSFT' >> fldnm=fieldnames(s)' %recording fieldnames of structure s fldnm = 'f1' 'f2' >> c=struct2cell(s)' %converting structure s to cell array c c = [10x10 double] 'MSFT' >> s2=cell2struct(c',fldnm) %converting cell array c to structure s2 using fldnm which was recorded earlier. For some reason MATLAB prefers column-vector c s2 = f1: [10x10 double] f2: 'MSFT'
cellfun(@function_name,cell1,cell2,...,celln,options)
evaluates a function
function_name
picking every first element of cell arrayscell1,cell2,...,celln
, every second element of cell arrayscell1,cell2,...,celln
, etc.>> c1={rand(10,10,10),rand(10,10,10),rand(10,10,10)}; >> c2={1,2,3}; >> average=cellfun(@mean,c1,c2, 'UniformOutput',0) average = [1x10x10 double] [10x1x10 double] [10x10 double]
Without
’UniformOutput’,0
MATLAB tries to construct a vector with three elements and fails for obvious reasons.