Difference between revisions of "Probability Norm Exercises"

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<li><p>[L1,L2] If <math>X\sim N(0,1)</math> evaluate</p>
 
<li><p>[L1,L2] If <math>X\sim N(0,1)</math> evaluate</p>
 
<ol>
 
<ol>
<li><p><math>\Pr (X\leq 0.2)</math></p></li>
+
<li><p><math>\Pr (X\leq 0.23)</math></p></li>
<li><p><math>\Pr (X\geq 0.2)</math></p></li>
+
<li><p><math>\Pr (X\geq 0.23)</math></p></li>
<li><p><math>\Pr (-0.5 \leq X \leq 1.8)</math></p></li></ol>
+
<li><p><math>\Pr (-0.5 \leq X \leq 1.84)</math></p></li></ol>
 
</li>
 
</li>
 
<li><p>[L1,L2] Find the number <math>z_{0}</math> such that if <math>Z\sim N(0,1)</math></p>
 
<li><p>[L1,L2] Find the number <math>z_{0}</math> such that if <math>Z\sim N(0,1)</math></p>

Revision as of 15:30, 4 September 2014

Exercises

  1. [L1,L2] If [math]X\sim N(0,1)[/math] evaluate

    1. [math]\Pr (X\leq 0.23)[/math]

    2. [math]\Pr (X\geq 0.23)[/math]

    3. [math]\Pr (-0.5 \leq X \leq 1.84)[/math]

  2. [L1,L2] Find the number [math]z_{0}[/math] such that if [math]Z\sim N(0,1)[/math]

    1. [math]\Pr (Z\geq z_{0})=0.05[/math]

    2. [math]\Pr (Z\lt -z_{0})=0.025[/math]

    3. [math]\Pr (-z_{0}\lt Z\leq z_{0})=0.95[/math]

    and check your answers using EXCEL.

  3. [L1,L2] If [math]X\sim N(4,0.16)[/math] evaluate

    1. [math]\Pr (X\geq 4.2)[/math]

    2. [math]\Pr (3.9\lt X\leq 4.3)[/math]

    3. [math]\Pr \left( (X\leq 3.8)\cup (X\geq 4.2)\right) [/math]

    and check your answers using EXCEL. (Note for part (c), define the “events” [math]A=\left( X\leq 3.8\right) [/math] and [math]B=\left( X\geq 4.2\right) [/math] and calculate [math]\Pr \left( A\cup B\right)[/math].

Footnotes